Electrical demand reduction calculations

When Projected Demand Average exceeds the Demand Limit value for the current Demand Interval, the system calculates how many loads to shed.

You should set all available (or desired) Power Shed Level properties (1-32) to a demand value based on the loads that are controlled by the specific shed group.

An estimate of the demand associated with a group of equipment can be calculated if the operating voltage and current draw are known for the loads. This is an example of a calculation for single-phase loads:

W = V * A

W = 120 Volts * 30 Amps = 3600 Watts = 3.6 kW

The following is an example using the square root of 3 for three-phase loads:

W = V * A * 1.73

W = 480 Volts * 30 Amps * 1.73 = 24919 Watts = 24.9 kW

Assume that the current demand limit period is Demand Limit Period1, and the ElectricalDemandLimit component is configured as follows:

Figure 4.   EDL example configuration
Image

In addition, the calculated total is 7625 kW and the Projected Demand Average is 533 kW. These equations show the kW that needs to be shed:

targetIntervalTotal = demandLimit * (minutesElapsed + minutesRemaining)

targetIntervalTotal = 500 * (11.25 + 3.75) = 7500

powerChange = (calculated total - targetIntervalTotal) / minutesRemaining

powerChange = (7625 - 7500) / 3.75 = 33.33 KW that needs to be shed

Since Power Shed Level1 is only expected to reduce the demand by 20 kW, both Power Shed Level1 and Power Shed Level2 must be shed to reduce the demand by an expected 35 kW combined.

The necessary loads are shed in sequential order during the same execution cycle, without evaluating the actual impact on demand.

The load shed determination is based on the projected reduction in demand for each group.

Subsequent calculations may result in additional load shedding if the actual demand is not reduced below the demand limit.